tests/tcg/mips: Add tests for R5900 DIV1
Add a test for DIV1. Reviewed-by: Aleksandar Markovic <amarkovic@wavecomp.com> Signed-off-by: Fredrik Noring <noring@nocrew.org> Signed-off-by: Aleksandar Markovic <amarkovic@wavecomp.com>
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@ -8,7 +8,8 @@ SIM_FLAGS=-cpu R5900
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CC = $(CROSS)gcc
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CFLAGS = -Wall -mabi=32 -march=r5900 -static
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TESTCASES = mflohi1.tst
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TESTCASES = div1.tst
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TESTCASES += mflohi1.tst
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TESTCASES += mtlohi1.tst
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TESTCASES += mult.tst
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TESTCASES += multu.tst
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73
tests/tcg/mips/mipsr5900/div1.c
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73
tests/tcg/mips/mipsr5900/div1.c
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@ -0,0 +1,73 @@
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/*
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* Test R5900-specific DIV1.
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*/
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#include <stdio.h>
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#include <inttypes.h>
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#include <assert.h>
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struct quotient_remainder { int32_t quotient, remainder; };
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static struct quotient_remainder div1(int32_t rs, int32_t rt)
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{
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int32_t lo, hi;
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__asm__ __volatile__ (
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" div1 $0, %2, %3\n"
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" mflo1 %0\n"
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" mfhi1 %1\n"
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: "=r" (lo), "=r" (hi)
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: "r" (rs), "r" (rt));
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assert(rs / rt == lo);
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assert(rs % rt == hi);
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return (struct quotient_remainder) { .quotient = lo, .remainder = hi };
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}
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static void verify_div1(int32_t rs, int32_t rt,
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int32_t expected_quotient,
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int32_t expected_remainder)
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{
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struct quotient_remainder qr = div1(rs, rt);
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assert(qr.quotient == expected_quotient);
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assert(qr.remainder == expected_remainder);
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}
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static void verify_div1_negations(int32_t rs, int32_t rt,
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int32_t expected_quotient,
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int32_t expected_remainder)
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{
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verify_div1(rs, rt, expected_quotient, expected_remainder);
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verify_div1(rs, -rt, -expected_quotient, expected_remainder);
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verify_div1(-rs, rt, -expected_quotient, -expected_remainder);
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verify_div1(-rs, -rt, expected_quotient, -expected_remainder);
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}
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int main()
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{
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verify_div1_negations(0, 1, 0, 0);
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verify_div1_negations(1, 1, 1, 0);
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verify_div1_negations(1, 2, 0, 1);
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verify_div1_negations(17, 19, 0, 17);
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verify_div1_negations(19, 17, 1, 2);
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verify_div1_negations(77773, 101, 770, 3);
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verify_div1(-0x80000000, 1, -0x80000000, 0);
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/*
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* Supplementary explanation from the Toshiba TX System RISC TX79 Core
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* Architecture manual, A-38 and B-7, https://wiki.qemu.org/File:C790.pdf
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*
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* Normally, when 0x80000000 (-2147483648) the signed minimum value is
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* divided by 0xFFFFFFFF (-1), the operation will result in an overflow.
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* However, in this instruction an overflow exception doesn't occur and
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* the result will be as follows:
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*
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* Quotient is 0x80000000 (-2147483648), and remainder is 0x00000000 (0).
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*/
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verify_div1(-0x80000000, -1, -0x80000000, 0);
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return 0;
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}
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