openpic: don't crash on a register access without a CPU context

If we access a register via the QEMU memory inspection commands (e.g.
"xp") rather than from guest code, we won't have a CPU context.
Gracefully fail to access the register in that case, rather than
crashing.

Signed-off-by: Scott Wood <scottwood@freescale.com>
Signed-off-by: Alexander Graf <agraf@suse.de>
This commit is contained in:
Scott Wood 2012-12-13 16:12:02 +00:00 committed by Alexander Graf
parent a26a7b3833
commit c3203fa5b2

View file

@ -161,7 +161,11 @@ static inline int test_bit(uint32_t *field, int bit)
static int get_current_cpu(void)
{
return cpu_single_env->cpu_index;
if (!cpu_single_env) {
return -1;
}
return cpu_single_env->cpu_index;
}
static uint32_t openpic_cpu_read_internal(void *opaque, hwaddr addr,
@ -810,6 +814,11 @@ static void openpic_cpu_write_internal(void *opaque, hwaddr addr,
DPRINTF("%s: cpu %d addr " TARGET_FMT_plx " <= %08x\n", __func__, idx,
addr, val);
if (idx < 0) {
return;
}
if (addr & 0xF)
return;
dst = &opp->dst[idx];
@ -875,6 +884,11 @@ static uint32_t openpic_cpu_read_internal(void *opaque, hwaddr addr,
DPRINTF("%s: cpu %d addr " TARGET_FMT_plx "\n", __func__, idx, addr);
retval = 0xFFFFFFFF;
if (idx < 0) {
return retval;
}
if (addr & 0xF)
return retval;
dst = &opp->dst[idx];