c096358e74
Not all platforms check whether a lock is initialized before used. In particular Linux seems to be more permissive than OSX. Check initialization state explicitly in our code to catch such bugs earlier. Signed-off-by: Fam Zheng <famz@redhat.com> Message-Id: <20170704122325.25634-1-famz@redhat.com> Signed-off-by: Paolo Bonzini <pbonzini@redhat.com>
48 lines
861 B
C
48 lines
861 B
C
#ifndef QEMU_THREAD_POSIX_H
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#define QEMU_THREAD_POSIX_H
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#include <pthread.h>
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#include <semaphore.h>
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typedef QemuMutex QemuRecMutex;
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#define qemu_rec_mutex_destroy qemu_mutex_destroy
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#define qemu_rec_mutex_lock qemu_mutex_lock
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#define qemu_rec_mutex_try_lock qemu_mutex_try_lock
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#define qemu_rec_mutex_unlock qemu_mutex_unlock
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struct QemuMutex {
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pthread_mutex_t lock;
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bool initialized;
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};
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struct QemuCond {
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pthread_cond_t cond;
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bool initialized;
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};
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struct QemuSemaphore {
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#if defined(__APPLE__) || defined(__NetBSD__)
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pthread_mutex_t lock;
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pthread_cond_t cond;
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unsigned int count;
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#else
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sem_t sem;
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#endif
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bool initialized;
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};
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struct QemuEvent {
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#ifndef __linux__
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pthread_mutex_t lock;
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pthread_cond_t cond;
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#endif
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unsigned value;
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bool initialized;
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};
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struct QemuThread {
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pthread_t thread;
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};
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#endif
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